physics

what average force is needed to accelerate a 7.00-gram pellet from rest to 125m/s over distance of a .800m along the barrel of a rifle.

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  1. a = (V^2-Vo^2)/2d.
    a = (15625-0)/1.60 = 9766 m/s^2.

    F = ma = 0.007 * 9766 = 68.4 N.

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  2. what steps did you take to get the numbers for (a)

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  3. V^2= U^2 + 2as
    125^2 = 2a(0.8)
    15625 = 1.6a
    a = 9765.62 m/s^2

    F = ma
    = (0.007)(9765.62)
    = 68.4 N

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  4. WHAT THE HELLA RE YOU GUYS DOING

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