if the ratio of oxygen to air is approximately 1 to 5 and the ratio of oxygen to ethyne is 2 to 5, how do i calulate the ratio of air to ethyne?

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  1. Write the balanced equation for ethyne reacting with oxygen; I assume that is the 2:5.
    Then g oxygen need for the combustion of ethyne x 1/0.2 = ??
    OR you need 5 times as much air as oxygen.

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  2. what is g

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  3. wat is g

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  4. I wrote g to stand for grams. So grams of oxygen you need (or tons or kilotons or what have you) x 5 will be g/tons/kilotons/whathaveyou of air you will need to obtain that much oxygen.

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