how many atoms are present in 80.0 mol of zirconium?

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  1. There is a constant in chemistry, know as Avogrado's number, which equals 6.023*10^23. This number equals the number of particles of a random material in exactly one mol of material. The mol is thus defined as containing exactly that number of particles. Now, since it's given that we have 80.0 mol of Zr, we just have to multiply this number with Avogrado's number to find the total amount of particles

    => amount of particles = 80*6.023*10^23
    = 481.84*10^23

    So there are roughly 481.84*10^23 atoms of 80 mol of Zr

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  2. lol idk you tell me broo

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