A 150g potato cools from 100 degrees Celsius to 50 degrees Celsius. If the specific heat capacity of the potato is 2000 j/kg degrees Celsius, how much heat does the potato lose?
q = mass x specific heat x delta T = ?
If you use mass in grams, you must change specific heat to 2 J/g*C and q will be in J.
20 000 J
-15000000
To calculate the amount of heat lost by the potato, you can use the formula:
Q = mcΔT
Where:
Q is the heat lost or gained
m is the mass of the object (in this case, the potato) in kilograms
c is the specific heat capacity of the substance (in this case, the potato) in joules per kilogram degrees Celsius
ΔT is the change in temperature of the object in degrees Celsius
To use this formula, you need to convert the mass of the potato from grams to kilograms. Since 1 kilogram is equal to 1000 grams, the mass of the potato is 150 grams ÷ 1000 = 0.15 kilograms.
The change in temperature of the potato is 100 degrees Celsius - 50 degrees Celsius = 50 degrees Celsius.
Now you can plug in the values into the formula:
Q = (0.15 kg) * (2000 J/kg degrees Celsius) * (50 degrees Celsius)
Q = 1500 joules
Therefore, the potato loses 1500 joules of heat.