Chemistry

Consider the reaction:
2HCl(aq) + Ba(OH)2(aq) → BaCl2(aq) + 2H2O(l)

∆H = - 118 kJ

Calculate the heat when 100.0 mL of 0.500 M HCl is mixed with 300.0 mL of 0.50 M Ba(OH)2. Assuming that the temperature of both solutions was initially 25 oC and the final mixture has a mass of 400.0 g and a specific heat 4.18 J/g oC, calculate the final temperature of the mixture.

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  1. 2H^+ + 2OH^- ==> 2H2O
    When 2 mol H^+ react with 2 mols OH^-, the heat produced is 118 kJ. Therefore it it 118/2 kJ/mol and we have 0.05 mols H^+ = 2.95 kJ.
    2,950 J = 400 g x specific heat x (Tf-25)
    Solve for Tf.

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