a 25 foot ladder leans against the wallit touches the wall 24 feet off the ground if you slide the base of the ladder back 10 feet off the ground how far does it slide down the wall?
Use the Pythagorean Theorem as I showed Jenny/Jeremy/you.
but there is an extra number
original position of foot of ladder
x^2+24^=25^
...
x = 7
so it moves out another 10 feet, so foot is 17 feet from wall
y^2 + 17^2 = 25^2
...
y^2 = 336
y = √336 = appr 18.3
well, it was up 24 feet and now is up only 18.3 feet,
so ....... ??
im confused how do u get 7
To determine how far the ladder slides down the wall when the base is moved, we can use the concept of similar triangles.
When the ladder touches the wall 24 feet off the ground, the distance along the ground from the base to the wall is 25 feet. Let's label this distance as "x".
Since we have a right triangle formed by the ladder, the ground, and the wall, we can use the Pythagorean theorem to find the length of the ladder:
(Length of ladder)^2 = (Height)^2 + (Base)^2
25^2 = 24^2 + x^2
625 = 576 + x^2
625 - 576 = x^2
49 = x^2
Taking the square root of both sides, we get:
x = sqrt(49)
x = 7
Therefore, when the base of the ladder is moved 10 feet off the ground, the ladder slides down the wall by 7 feet.