# PHYSICS

A speeder passes a parked police car at a constant speed of 25.1 m/s. At that instant,the police car starts from rest with a uniform acceleration of 2.86 m/s^2.

1) How much time passes before the speeder is overtaken by the police car?
2) How far does the speeder travel before being overtaken by the police car?

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1. 1. 25.1t = 0.5a*t^2.
1.43t^2 - 25.1t = 0
t = 17.55 s.

2. d = 25.1 + 17.55 = 440.5 m.

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