Math

In a trapezium ABCD,ABperpendicular DC.if angle A=4x degree,angle B=(6x+10degree),angle C=(3x-10degree) & angle D=5x degree.find each angle of trapezium.

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  1. The angle sum of a trapezium must be 360° , so

    4x + 6x+10 + 3x-10 + 5x = 360
    18x = 360
    x = 20

    angle A = 80°
    angle B = 130°
    angle C = 50°
    angle D = 100°

    I don't see any perpendicular sides.
    Your question contains a contradiction.

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  2. I think he meant AB parallel to DC, if vertices are labeled in cyclic order

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