What is the midpoint of line BC with B (2,0) and C (-4,6)?
(-1,3)
Make sure to use the midpoint formula!
X 1 + X2 Y1 +Y2
________ _______
2 2
To find the midpoint of line BC with the given coordinates of points B and C, we can use the midpoint formula. The midpoint formula determines the coordinates of the point that is exactly halfway between two given points.
The midpoint formula is:
Midpoint = ((x1 + x2)/2, (y1 + y2)/2)
Let's apply this formula to the given points B(2,0) and C(-4,6):
For the x-coordinate of the midpoint:
x1 = 2 (the x-coordinate of point B)
x2 = -4 (the x-coordinate of point C)
Substituting these values into the formula:
x-coordinate of the midpoint = ((2 + (-4))/2) = (-2)/2 = -1
For the y-coordinate of the midpoint:
y1 = 0 (the y-coordinate of point B)
y2 = 6 (the y-coordinate of point C)
Substituting these values into the formula:
y-coordinate of the midpoint = ((0 + 6)/2) = 6/2 = 3
Therefore, the coordinates of the midpoint of line BC are (-1, 3).