A solution is made by dissolving 1.0 mole of Na2SO4(ionic compound) into water to get 1.0L of solution. Give the conc of all the ions present in solution in M?
(Na23SO4) = mols/L = 1.0mol/1.0L = 1 M.
(Na+) = 2 x M Na2SO4
(SO4^2-) = M Na2SO4
To determine the concentration of ions in the solution, we first need to recognize that Na2SO4 dissociates in water into three ions: 2 Na+ ions and 1 SO42- ion.
Given that you have 1.0 mole of Na2SO4 dissolved in 1.0L of solution, we can use the mole-to-molarity relationship to calculate the concentrations.
Step 1: Calculate the number of moles of Na2SO4:
Given: 1.0 mole Na2SO4
Step 2: Calculate the concentration (molarity) of Na+ ions:
Since 1 mole of Na2SO4 yields 2 moles of Na+ ions, the concentration of Na+ ions is 2 times the concentration of Na2SO4.
Concentration of Na+ ions = (2 moles / 1 L) = 2 M
Step 3: Calculate the concentration (molarity) of SO42- ions:
Since 1 mole of Na2SO4 yields 1 mole of SO42- ions, the concentration of SO42- ions is the same as the concentration of Na2SO4.
Concentration of SO42- ions = (1 mole / 1 L) = 1 M
So, the concentration of Na+ ions in the solution is 2 M, and the concentration of SO42- ions is 1 M.