Physics

A woman weighing 500 N stands in an elevator that is traveling upward. At a given instant the speed of the elevator as well as the women is 10m/s and both are decreasing at a rate of 2 m/s2 at that instant the elevator is exerts a force on the woman that is

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  1. a↓ mg↓ N↑
    ma =mg-N
    N=mg-ma =
    =W-(W/g) •a=
    =500 –(500/9.8) •2 =398 N

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