explain why f(x)=(1)/(x^2-9) is discontinoues at x=-3
it is discontinuous there because division by zero is not defined.
A continuous function has no "holes" in it. f(x) is not defined for x = 3 or -3, because x^2-9 is zero there.
A continuous function has no "holes" in it. f(x) is not defined for x = 3 or -3, because x^2-9 is zero there.