Physics

A boy sledding down a hill accelerates at 1.25 m/s2. If he started from rest, in what distance would he reach a speed of 5.00 m/s?

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asked by Dakota
  1. d = (V^2-Vo^2)/2a = (25-0) / 2.5 = 10 m.

    posted by Henry
  2. 6.25

    posted by billy

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