Physics

when driving at night at a speed of 80 km/hr, a deer suddenly appeared and frozen in your head light. The distance between your car and the deer was 45 meters at the moment you start to break your car as hard as possible in order to avoid the accident Assume that you could only generate a deceleration of -6m/s2 on your car, would both you and the deer be safe

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  1. 100 km

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  2. v=80000/3600 = 22.2 m/s
    the car decelerated at the distance
    s1=v²/2•a=22.2²/2•6=41.15 m

    41.15< 45 m
    The driver and the deer will be safe

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