Two motorcycles are traveling due east with different velocities. However, four seconds later, they have the same velocity. During this four-second interval, cycle A has an average acceleration of 1.8 m/s2 due east, while cycle B has an average acceleration of 3.8 m/s2 due east. By how much did the speeds differ at the beginning of the four-second interval?
Which motorcycle was moving faster?

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  1. If cycle A had velocity a, and
    cycle B had velocity b,

    a + 1.8*4 = b + 3.8*4
    a-b = 8

    a was going 8m/s faster than b

    makes sense, since b accelerated faster, yet wound up with same speed.

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  2. -7.36

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