# Physics

A speed skater moving across frictionless ice at 8.0 m/s hits a 5.7m-wide patch of rough ice. She slows steadily, then continues on at 6.5m/s.

What is her acceleration on the rough ice?

1. 5.7 = 8t + 1/2 at^2
6.5 = 8 + at

a = -1.9079 m/s^2
t = 0.7862 s

posted by Steve

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