College Physics I

A helicopter traveling upward at 120 m/s drops a package from a height of 500 meters. To the nearest second how long does it take to hit the ground?

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  1. I believe that there is mistake in your given data: the velocity has to be 12 m/s

    There are two motions of the package:
    1. upward motion with the initial velocity of 12 m/s
    h=vₒ²/2g =144 /2•9.8 =7.34 m
    H=500+7.34 =507.34 m
    2. Dowmward motion (free fall)
    t=sqrt(2H/g)=sqrt(2•507.34/9.8) =10.18 s.
    If the speed is 120 m/s, calculate using your numbers.

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