what is the symbol for the element that has 78 protons
76 electrons
117 neutrons and a +2 net charge? i thought it was ^195Os^+2 but that is wrong. Thanks for the help!
If it has 78 protons it MUST be Pt (look at the periodic table) so I would write
195Pt^2+.
Note: The atomic number is the number of protons; not the number of electrons.
To determine the symbol for the element with the given properties, we can use the information provided.
The atomic number of an element represents the number of protons it has. In this case, the element has 78 protons.
The atomic number also determines the number of electrons in a neutral atom, which is equal to the number of protons. So, the number of electrons in this element would also be 78.
To find the number of neutrons, we subtract the atomic number (protons) from the mass number. The mass number is the sum of protons and neutrons. In this case, the mass number would be 78 + 117 = 195.
Lastly, the net charge of the atom is given as +2. This means that the atom has lost 2 electrons, resulting in a net positive charge. Since the number of electrons is equal to the number of protons in a neutral atom, we subtract 2 from the atomic number to account for the lost electrons. Therefore, the atomic number of this ion is 78 - 2 = 76.
Putting all the information together, the symbol for the element with 78 protons, 76 electrons, 117 neutrons, and a +2 net charge would be:
^195Pt^2+
So, the correct symbol for this element is platinum (Pt) with a mass number of 195 and a +2 charge.
To determine the symbol for an element, you need to know its atomic number (number of protons) and atomic mass (number of protons plus neutrons). The net charge on an element is calculated by subtracting the number of electrons from the number of protons.
In this case, you mentioned that the element has 78 protons and 76 electrons, resulting in a net charge of +2. This means that the element should have two more protons than electrons.
To find the atomic mass, you can add the number of protons (78) to the number of neutrons (117). Therefore, the atomic mass of this element is 78 + 117 = 195.
Now let's find the symbol for this element. The symbol consists of the element's atomic number as a subscript and the element's atomic mass as a superscript.
Based on the information provided, the correct symbol for the element you described is:
78^195Os^2+
Note that the atomic number is always a subscript, while the atomic mass and charge are always superscripts.