college algebra

determine the quadratic function f whose graph is given.
the vertex is (1,-3)
y intercept is -2

please show work so i can see how this is done, thank you!

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  1. For a vertex of (1,-3) the equation is
    Y= a(x-1)^2 - 3
    But (0,-2)lies on it, so
    -2 = a(0-1)^2 -3
    1 = a


    Y = (x-1)^2 - 3

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  2. Find the equation of the quadratic Functions whose graph is a parabola the points (-2,19), (3,14) and (4,25)

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