math

please help!

1.) A random digit from 1 to 9 (inclusive) is chosen, with all digits being equally likely. The probability that when it's squared it will end with the digit 1.

2.) A random number between 1 and 20 (inclusive) is chosen. The probability that its square root will not be an integer.

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  1. See response to:
    http://www.jiskha.com/display.cgi?id=1344678011

    and post if you need more explanations or would like to post your attempt.

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  2. thank you for your help!
    can you check if it's correct?

    1.) 1/9
    2.) 4/2= 1/5

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  3. 1.
    Note that
    21*21=441
    49*49=2401
    Does that give you a hint?

    2.
    The question looks for
    "The probability that its square root will not be an integer"
    so check your answer accordingly.

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  4. Question: why is it not 2/9? Since I know 1 squared will be 1, which ends in 1, but what about 9? 9 squared is 81, it ends in 1. So that makes 2/9 = 0.22

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  5. Question: why is it not 2/9? Since I know 1 squared will be 1, which ends in 1, but what about 9? 9 squared is 81, it ends in 1. So that makes 2/9 = 0.22

    @MathMate

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