# math

1.) A random digit from 1 to 9 (inclusive) is chosen, with all digits being equally likely. The probability that when it's squared it will end with the digit 1.

2.) A random number between 1 and 20 (inclusive) is chosen. The probability that its square root will not be an integer.

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3. 👁 963
1. See response to:
http://www.jiskha.com/display.cgi?id=1344678011

and post if you need more explanations or would like to post your attempt.

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2. thank you for your help!
can you check if it's correct?

1.) 1/9
2.) 4/2= 1/5

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3. 1.
Note that
21*21=441
49*49=2401
Does that give you a hint?

2.
The question looks for
"The probability that its square root will not be an integer"

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4. Question: why is it not 2/9? Since I know 1 squared will be 1, which ends in 1, but what about 9? 9 squared is 81, it ends in 1. So that makes 2/9 = 0.22

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5. Question: why is it not 2/9? Since I know 1 squared will be 1, which ends in 1, but what about 9? 9 squared is 81, it ends in 1. So that makes 2/9 = 0.22

@MathMate

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