chemistry

A solution of sodium cyanide NACN has a PH of 12.10. How many grams of NACN are in 425ml of solution with the same PH?

Please helps me to solve it for me

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  1. How to calculate PH 1.9 = 0.0126M Why?
    How to calculate PH 1.8 = ?
    How to calculate PH 20 = ?
    How to calculate PH 21 = ?

    Pls helps me

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  2. pH = -log(H^+)
    1.9 = -log(H^+)
    -1.9 = log(H^+).
    (H^+) = 0.01259 which rounds to 0.126
    The others are done the same way.

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  3. pH = 12.10
    pH + pOH = pKw = 14
    Substitute and sole for pOH. You should get 1.9 for pOH, then
    pOH = -log(OH^-) and (OH^-) = 0.0126M.

    0.0126M mans 0.0126 mols/L soln. For 425 mL you will have 0.0126 mol x (425/1000) = about 0.00536 mols. Then grams = mols x molar mass NaCN.

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  4. I do not still understand how to calculate PH 1.9 = 0.0126M
    I want step by step to calculate for me.

    Thank you for your help.

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