Statistics

A random sample of customer incomes yields a mean income of $35000 with a standard deviation of $4500. Assume that the distribution of the incomes in normal. What income range would include 90% of the most popular incomes?

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  1. Given:
    μ=35000
    σ=4500
    X~N(35000,4500^2)

    Look for the two tail probability in the normal distribution table for 90% = 0.9, or
    Z=±1.645
    So the range that contains 90% would be between μ±1.645*σ

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