how to solve log basex 8=-1/2
pls help
http://www.jiskha.com/display.cgi?id=1342557692
log basex8= -1/2
so rearrange it, therefore
x^-1/2 = 8
1/root(x) = 8
8root(x)=1
root(x)=1/8
x = (1/8)^2
so ur answer for x is x= 1/64
To solve the logarithmic equation logₓ 8 = -1/2, we want to find the value of x that satisfies this equation. Here's how you can do it step by step:
Step 1: Rewrite the equation using exponential notation:
x^(-1/2) = 8
Step 2: Take the reciprocal of both sides:
1 / x^(1/2) = 8
Step 3: To eliminate the fraction, square both sides of the equation:
(1 / x^(1/2))^2 = 8^2
Simplifying further:
1 / x = 64
Step 4: Now, take the reciprocal of both sides again:
x = 1 / 64
Therefore, the solution to the equation logₓ 8 = -1/2 is x = 1/64.