Given y=(x^2+2)sqrt(x^3-8x) Find dy/dx
y = uv where u=x^2+2 and v=√(x^3-8x)
y' = u'v + uv'
= (2x)√(x^3-8x) + (x^2+2)*(1/2)(1/√(x^3-8x))*(3x^2-8)
= (7x^4 - 34x^2 - 16)/[2√(x^3-8x)]
y' = u'v + uv'
= (2x)√(x^3-8x) + (x^2+2)*(1/2)(1/√(x^3-8x))*(3x^2-8)
= (7x^4 - 34x^2 - 16)/[2√(x^3-8x)]