A block of mass 77.0kg is placed at the top of a frictionless plane that is inclined 46 degrees to the horizontal. The height of the plane is 23.0 meters. Find the speed of the block at the bottom of the plane.
Please show all your steps, don't just suggest a formula.
Thank you so much.
PE -> KE,
PE=KE,
KE=m•v²/2,
PE=m•g•h,
m•g•h =m•v²/2,
v=sqrt(2 g•h).