# GEOMETRY

The diameter of a circle has endpoints P(–10, –2) and Q(4, 6).
a.Find the center of the circle.
b.Find the radius. If your answer is not an integer, express it in radical form.
c.Write an equation for the circle.

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1. The centre must be the midpoint of PQ
which would be C( (-10+4)/2 , (-2+6)/2 )
= C(-3,2)

radius is √( (4+3)^2 + (2-6)^2) = √65

equation:
(x+3)^2 + (y-2)^2 = 65

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2. Length of the diameter of a circle with the endpoints A(4, -3) and B(4, 3)

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3. -6, -2 2, 4

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4. first one is right

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5. omg this is from 2012

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6. P(-10, -2), C(x, y), Q(4, 6).
a. x+10 = 1/2(4+10)
X = -3.
y+2 = 1/2(6+2)
Y = 2.

b. Radius = sqrt ((-3+10)^2+(2+2)^2) = sqrt 65.

c. (x+10)^2+(y+2)^2 = 65.

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7. a. To find the center of the circle, we use the midpoint formula. ((-10+4)/2 , (-2+6)/2 )= C(-3,2). The center is at (-3,2).
b. d = √((x_2 - x_1)^2 + (y_2-y_1)^2)
d=√((-3 - 4)^2 + (2-6)^2)
d=√((-7)^2 + (-4)^2)
d=√(49 + 16)
d=√(65)
Radius=√(65)
c. (x+3)^2+(y-2)^2 = 65.

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