# GEOMETRY

The diameter of a circle has endpoints P(–10, –2) and Q(4, 6).
a.Find the center of the circle.
c.Write an equation for the circle.

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1. The centre must be the midpoint of PQ
which would be C( (-10+4)/2 , (-2+6)/2 )
= C(-3,2)

radius is √( (4+3)^2 + (2-6)^2) = √65

equation:
(x+3)^2 + (y-2)^2 = 65

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2. Length of the diameter of a circle with the endpoints A(4, -3) and B(4, 3)

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3. -6, -2 2, 4

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4. first one is right

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5. omg this is from 2012

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6. P(-10, -2), C(x, y), Q(4, 6).
a. x+10 = 1/2(4+10)
X = -3.
y+2 = 1/2(6+2)
Y = 2.

b. Radius = sqrt ((-3+10)^2+(2+2)^2) = sqrt 65.

c. (x+10)^2+(y+2)^2 = 65.

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