Precalculus check answers help!

1.) Find an expression equivalent to sec theta sin theta cot theta csc theta.
tan theta
csc theta
sec theta ~
sin theta

2.) Find an expression equivalent to cos theta/sin theta .
tan theta
cot theta ~
sec theta
csc theta

3.) Simplify (tan^2 theta + 1)/(tan^2 theta) .
csc2 theta
–1
tan2 theta
1 ~

4.) Use a sum or difference identity to find the exact value of sin 15°.
-(sqrt)2 - (sqrt)6/ 4
(sqrt)6 - (sqrt)2/ 4 ~
(sqrt)6 + (sqrt)2/ 4
(sqrt)2 - (sqrt)6/ 4

5.) Which expression is equivalent to cos (theta – 2pi)?
–cos theta
sin theta
cos theta ~
–sin theta

the ones with ~ are my answers!

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  1. 1), 3) check your algebra

    4) I'm not sure where you went wrong on this one. However, sqrt(6)-sqrt(2)/4 is greater than 1 (2.0959 in fact)

    2), 5) are correct

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  2. is 3 -1?
    and im not sure what i did on number 1 ? please explain.

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  3. 1)
    secØ sinØ cotØ cscØ
    = (1/cosØ)(sinØ)(cosØ/sinØ)(1/sinØ)
    = 1/sinØ
    = cscØ

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  4. find an expression equivalent: sec θ - sin θ tan θ=

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