Question 1.
A Compound Containing 3 Atoms Of Carbon & 8 Atoms Of Hydrogen Is Combined In A Reaction With Oxygen Molecules. The 2 End Products Of This Equation Are Carbon Dioxide &water. What Element Should You Look At 1st In Balancing This Equation? Choose a.b.c or d?
A. Oxygen
b. Hydrogen
c. Carbon
d. Dioxide
Question 2 NEW QUESTION
When you have finished balancing the equation for the above question, which chemical element will have the largest number of molecules in your balanced equation? Choose a. B. C. Or d?
A. The C3H
b. The oxygen
c. The carbon dioxide
d. The water
I think the correct answer is to question 1 - C.
C3H8 + O2 -----> CO2 + H2O
And the answer to question 2 is id D.
Option D) The water has the largest number of molecules in the balanced equation.
Personally, I don't like question 1 because many people balance equations differently. In addition, this one just happens to be a redox equation and it COULD be balanced that way instead of by inspection. At any rate, I would start with C also; therefore, in the spirit of the question, I think your answer is correct.
I don't like the second part of the question for a variety of reasons, either, but I won't go into them here unless you wish.
You have not answered part 2 correctly.
The balanced equation is
C3H8 + 5O2 ==> 3CO2 + 4H2O.
Therefore, the correct answer is oxygen has the largest number of molecules. [Note the question. It says to name the ELEMENT......] but I don't think it is a trick question. The point I am making is oxygen is the only ELEMENT standing alone in the entire equation so no matter what the coefficient is, oxygen is the correct answer.
oxygen
To balance the equation C3H8 + O2 → CO2 + H2O, we need to equalize the number of atoms on both sides of the equation. Here is the step-by-step process to balance the equation:
1. Start with the carbon atoms: There are 3 carbon atoms on the left side (in C3H8) and only 1 carbon atom on the right side (in CO2). To balance this, place a coefficient of 3 in front of CO2:
C3H8 + O2 → 3CO2 + H2O
2. Move on to the hydrogen atoms: There are 8 hydrogen atoms on the left side and 2 hydrogen atoms on the right side. To balance this, place a coefficient of 4 in front of H2O:
C3H8 + O2 → 3CO2 + 4H2O
3. Finally, balance the oxygen atoms: There are 2 oxygen atoms on the left side (in O2) and 10 oxygen atoms on the right side (in CO2 and H2O combined). To balance this, place a coefficient of 5/2 (2.5) in front of O2:
C3H8 + (5/2)O2 → 3CO2 + 4H2O
However, in order to have whole numbers as coefficients, multiply the entire equation by 2:
2C3H8 + 5O2 → 6CO2 + 8H2O
Now, let's move on to question 2.
Looking at the balanced equation:
2C3H8 + 5O2 → 6CO2 + 8H2O
We can determine which chemical element has the largest number of molecules by comparing the coefficients in front of each compound.
The largest coefficient is in front of H2O, which is 8. Therefore, the answer to question 2 is:
Option d) The water has the largest number of molecules in the balanced equation.