Find the axis of symmetry:
y=x^2-8x-7 i got 4....am i right?
correct. You wind up with
y = (x-4)^2 - 23
Correct. This is a parabola with a vertical axis of symmetry (x = 4).
To find the axis of symmetry, you can use the formula x = -b/2a, where a, b, and c are the coefficients of the quadratic equation in the form ax^2 + bx + c.
In the given equation, y = x^2 - 8x - 7, the coefficient of x^2 is 1 (a = 1) and the coefficient of x is -8 (b = -8).
Now, you can substitute these values into the formula:
x = -(-8) / 2(1)
x = 8 / 2
x = 4
So, the axis of symmetry is x = 4. Therefore, your answer is correct.