An object moving in the positive x direction went from a velocity of 2.5 km/s to a velocity of 8.0 km/s in 6.2 seconds. What's the object's average acceleration?
v1 =2.5 km/s = 2500 m/s,
v2 = 8 km/s = 8000 m/s.
a =(v2-v1)/Δt = (8000-2500)/6.2 =
=887.1 m/s²
To find the average acceleration of an object, you need to use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, you need to convert the velocities from km/s to m/s, since the SI unit for velocity is meters per second. You can do this by multiplying the velocities by 1000:
Initial velocity = 2.5 km/s = 2.5 * 1000 m/s = 2500 m/s
Final velocity = 8.0 km/s = 8.0 * 1000 m/s = 8000 m/s
Now, substitute these values into the formula:
Average acceleration = (8000 m/s - 2500 m/s) / 6.2 s
Calculating the difference in velocities:
Average acceleration = 5500 m/s / 6.2 s
Finally, divide the calculated difference in velocities by the time to find the average acceleration:
Average acceleration ≈ 887.10 m/s²
So, the object's average acceleration is approximately 887.10 m/s² in the positive x direction.