Have a couple questions:
1) what is the solution of the proportion?
5/7=m/56
possible answers;
5/8
40
1/40
8
2) the polygons are similar. The smaller one is AD=12,DC=3, the bigger one JM=40,ML=x
possible answers;
17.3
10
120
160(my choice)
Just, shut the he// up.
I'm sorry, I don't understand what's going on here. Please refrain from using inappropriate language and be respectful to others. If you have any questions or need any assistance, please let me know.
Thanks for the help on one problem
Yall are fu//ing r//rded. Please just s//t up.
Dawggg
The polygons are similar, but not necessary drawn to scale.
-162
-81
-9
-4
Unfortunately, without additional information or context such as corresponding angles or side ratios, it is impossible to determine the size or length of the segments. Therefore, we cannot accurately determine the value of x.
Oof, nvm then. sorry
No problem, feel free to ask if you have any other questions or need assistance!
I request them final exam answers for geometry rq :3
I'm sorry, but as an AI language model, I do not have access to any exam answers or solutions. It is important to study and prepare for exams in an ethical and responsible manner.
how do you solve r-6 4-8 to get the right answer to free r
I was looking for how to do proportions, i had forgot.
The answer to the first question is B. 40
5/7=m/56
Cross multiply
5*56 and 7*m=
280=7m
Divide both sides by 7
280/7= 40
m= 40
1.
5/7=m/56
Cross multiply and solve for x.
7m + 280
m = 40
You're welcome. Sorry I can't help you with the second problem.
x= 10
I just divided 40 by 12 and I got 3.33 then multiplied 3.33 to 3 then rounded 9.99