How many moles are in 4.36 L of oxygen gas at STP?
4.36 L x (1 mol/22.4L) = ?
To determine the number of moles present in 4.36 L of oxygen gas at standard temperature and pressure (STP), we can use the ideal gas law and the molar volume at STP.
The molar volume at STP is defined as 22.4 L/mol, which means that one mole of any gas occupies 22.4 liters of volume at STP.
To find the number of moles, we can follow these steps:
1. Convert the given volume from liters to moles using the molar volume at STP:
Moles = Volume (L) / Molar Volume (L/mol)
= 4.36 L / 22.4 L/mol
2. Calculate the number of moles:
Moles = 0.194643 mol
Therefore, there are approximately 0.194643 moles of oxygen gas in 4.36 L at STP.
To determine how many moles are in 4.36 L of oxygen gas at STP (Standard Temperature and Pressure), you need to use the Ideal Gas Law equation:
PV = nRT
Where:
P = pressure in atmospheres (atm)
V = volume in liters (L)
n = number of moles
R = ideal gas constant (0.0821 L * atm / (mol * K))
T = temperature in Kelvin (K)
At STP, the temperature is 273.15 K, and the pressure is 1 atmosphere.
So, the equation becomes:
(1 atm) * (4.36 L) = n * (0.0821 L * atm / (mol * K)) * (273.15 K)
Now, we can solve for n (number of moles of oxygen gas).
n = (1 atm * 4.36 L) / (0.0821 L * atm / (mol * K) * 273.15 K)
n = 0.168 mol
Therefore, there are approximately 0.168 moles of oxygen gas in 4.36 L at STP.