1.)A rock at the blank of a coast is struck by water waves.find the frequency of the waves striking the rock,if the distance between two consecutive crests or troughs is 100m.velocity of water wave is 150m/sec.
2.)the timeperiod of a vibrating body is 0.1sec.the waves produced by the body moves with a speed of 330m/s.find the wavelength of the wave.
1.) To find the frequency of the waves striking the rock, we can use the formula:
Frequency = Velocity / Wavelength
Given:
Velocity of water wave = 150 m/s
Distance between two consecutive crests or troughs (wavelength) = 100 m
Substituting the values into the formula:
Frequency = 150 m/s / 100 m = 1.5 Hz
Therefore, the frequency of the waves striking the rock is 1.5 Hz.
2.) To find the wavelength of a wave, we can use the formula:
Wavelength = Velocity / Frequency
Given:
Speed of the wave = 330 m/s
Time period (T) = 0.1 s (1 cycle)
The frequency (f) can be calculated as the inverse of the time period:
f = 1 / T = 1 / 0.1 s = 10 Hz
Substituting the values into the formula:
Wavelength = 330 m/s / 10 Hz = 33 m
Therefore, the wavelength of the wave is 33 meters.
1.) To find the frequency of the water waves striking the rock, we can use the formula:
Frequency (f) = Velocity (v) / Wavelength (λ)
Given that the velocity of the water wave is 150 m/s and the distance between two consecutive crests or troughs is 100 m, we can substitute these values into the formula:
f = 150 m/s / 100 m = 1.5 Hz
Therefore, the frequency of the waves striking the rock is 1.5 Hz.
2.) To find the wavelength of the wave produced by the vibrating body, we can use the formula:
Wavelength (λ) = Velocity (v) × Time Period (T)
Given that the velocity of the wave is 330 m/s and the time period of the vibrating body is 0.1 s, we can substitute these values into the formula:
λ = 330 m/s × 0.1 s = 33 m
Therefore, the wavelength of the wave is 33 meters.
λ = v /f ,
1) f= v/λ =150/100 = 1.5 Hz
2) λ = v•T =330•0.1 = 33 m
λ = v /f .
1) f= v/λ =150/100 = 1.5 Hz
2) λ = v•T =330•0.1 = 33 m