# math

{y-2}/(a^2-5a+6)=(a+1)/(a-3)-(a+2)/(a-2)

How can I solve for y in terms of the other variables???
I tried many times, but I just get y=6,can't express y in terms of variables.
Can anyone please correct me or teach me?THANKS A LOT!

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1. The denominator of the left side factors to
(a-2)(a-3) which just happen to be found as denominators on the right side.

so...
if we multiply both sides by (a-2)(a-3) we get
y - 2 = (a+1)(a-2) - (a+2)(a-3)

expand the right sided, take the -2 over to the right side, and collect your like terms.
You are done!

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2. that means that still equal to 6 right?

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3. gee, I guess you are right!

both the a^2 and the a term drop out.

I should have finished my solution, :)

y = 6 !!!!

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4. however,6 is not a variable..the question is asking to solve for y in terms of other variables

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5. why don't you state in your solution that the variables canceled out?

In this case you were not able to solve in terms of the other variable.
In other words y was not a function of a

I suppose one could get silly and write

y = 6 + 0a

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