Two children balance on opposite ends of a seesaw. One child weighs 45 pounds and the other weighs 38 pounds. The distance between them is 10 feet. What is the distance of each child from the fulcrum (the center balance point of the seesaw)? (HINT: The product of the distance from the fulcrum and the weight of the chid must be equal on both sides of the fulcrum in order to balance the seesaw.
The hint says it all:
45x = 38(10-x)
solve for x. Now, decide which child is "x" from the fulcrum.posted by Steve
Fyygdeitposted by Mike