Physics

An object moves with acceleration given by a = -6t^3 m/s^2. Its initial velocity at t = 0 is 5 m/s. How far will it move before stopping?

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  1. Assume that t is measured in seconds.
    The velocity at time t is 5 + a t = 5 - 6t^4
    It stops when V = 0.
    5 - 6t^4 = 0 when t^4 = 5/6

    t = the fourth root of 5/6
    That is about 0.955 s.

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