Need help balancing chemical equation. Complete and balance the chemical equation. Be sure to include the states of the reactants and products.

C3H8(g)+O2(g) →

This is an example of a combustion reaction involving a hydrocarbon (in this case propane) reacting with oxygen. The products of such reactions are almost always water and carbon dioxide.

C3H8(g) + O2(g) → H2O + CO2

First balance the number of Carbons on both sides. There are 3 Carbon atoms for every propane molecule and 1 for each carbon dioxide.

C(3)H8(g) + O2(g) → H2O + _X_CO2

Second balance the number of Hydrogens. Here we have 8 for each propane and 2 for each water.

C3H(8)(g) + O2(g) → _Y_H(2)O + X*CO2

Finally count up all the oxygen atoms on the right side of the equation and balance that with the oxygen molecules on the left.

C3H8(g) + _Z_O2(g) → Y*H2O + X*CO2
where Z = X/2 + Y

Sometimes after this you will end up with fractions, which is okay, but if you prefer you can multiply both sides of the equation by the lowest common denominator to get rid of the fractions. In this case you shouldn't have any fractions.

Oh, and don't forget to include the states. CO2 is obviously a gas and H2O will likely also be a gas (water vapor) due to the heat yielded by the reaction.

Hope this helps.

2[C3H8]+7O2 - 3[CO2](g)+8[H2O](l)

2[C3H8] +7O2 - 3[CO2](g) + 8[H2O](l)

To balance the given chemical equation C3H8(g) + O2(g) → ?, we need to ensure that there are equal numbers of atoms on both sides of the equation.

1. Start by counting the number of atoms on each side of the equation:
Reactant side:
Carbon (C): 3
Hydrogen (H): 8
Oxygen (O): 2

Product side:
Carbon (C): ?
Hydrogen (H): ?
Oxygen (O): ?

2. Balance the carbon atoms:
Since there are three carbon atoms on the reactant side, we need to have three carbon atoms on the product side as well.
C3H8(g) + O2(g) → 3CO2(g)

3. Balance the hydrogen atoms:
Since there are eight hydrogen atoms on the reactant side, we need eight hydrogen atoms on the product side.
C3H8(g) + O2(g) → 3CO2(g) + 4H2O(g)

4. Balance the oxygen atoms:
On the reactant side, we have only two oxygen atoms from O2.
On the product side, there are six oxygen atoms from three CO2 molecules and four oxygen atoms from four H2O molecules.
To balance the oxygen atoms, we need to add four O2 molecules to the reactant side.
C3H8(g) + 4O2(g) → 3CO2(g) + 4H2O(g)

The balanced chemical equation is:
C3H8(g) + 4O2(g) → 3CO2(g) + 4H2O(g)

Note: The "(g)" represents the state of matter, with "(g)" indicating that the substance is a gas.