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The 6th term of an A.P is twice the third and the first term is 3. Find the common difference and the 10th term.

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  1. 3+5d = 2(3+2d)
    3+5d = 6+4d
    d = 3

    So, the sequence is

    3, 6, 9, 12, 15, 18, 21, 24, 27, 30 ...

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  2. as d=3
    a10=3+(10-1)3
    =30

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  3. 3+5d=2(3+2d)
    3+5d=6+4d
    d=3
    Imply formula to get the sequence

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  4. Iam not understand how do you got this answers

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  5. I don't understand how you got your answer

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