# calculus

how do you integrate

x^2/(9+x^6)

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1. Let u = x^3, so that
du/3 = x^2 dx
The integral of x^2 dx/(9+x^6) then becomes
(1/3) Integral of du/(9+ u^2)
= (1/3)(1/3)tan^-1(u/3)
= (1/9)tan^-1(x^3/3)

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