calculus

how do you integrate

x^2/(9+x^6)

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  1. Let u = x^3, so that
    du/3 = x^2 dx
    The integral of x^2 dx/(9+x^6) then becomes
    (1/3) Integral of du/(9+ u^2)
    = (1/3)(1/3)tan^-1(u/3)
    = (1/9)tan^-1(x^3/3)

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