What is the slope of the line described by the equation below?
y - 9 = -2(x - 8)
first put it in slope intercept form
y=mx +b
m is the slope and b will give you the y intercept
y-9 = -2(x-8)
multiply everyting in the parenthesis by -2
y-9= -2x + 16
and then plus 9 from both side
y= -2x + 25
your slope is -2
the equation is in the form
y - y1 = m(x - x1) where (x1, y1) is a point and m is the slope.
By the "just-looking-at it" principle, the slope is -2
(and a point on it is (8,9) )
To find the slope of the line described by the equation y - 9 = -2(x - 8), we need to rewrite the equation in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.
Starting with the given equation:
y - 9 = -2(x - 8)
Distribute the -2 to the terms inside the parentheses:
y - 9 = -2x + 16
Now, isolate the variable y:
y = -2x + 16 + 9
Simplify:
y = -2x + 25
Comparing this equation to the slope-intercept form, we can see that the slope (m) is -2. So, the slope of the line described by the equation is -2.
To find the slope of the line described by the given equation, we need to rewrite the equation in slope-intercept form (y = mx + b), where 'm' represents the slope of the line.
Let's begin by simplifying the equation:
y - 9 = -2(x - 8)
First, distribute -2 to both terms inside the parentheses:
y - 9 = -2x + 16
Next, move -9 to the right side of the equation by adding 9 to both sides:
y = -2x + 16 + 9
y = -2x + 25
Now the equation is in slope-intercept form (y = -2x + 25), where the coefficient of 'x' (-2) represents the slope of the line. In this case, the slope of the line is -2.