a car of mass 900 kg move at 10 m/s. What is the braking force required to stop the car in a time of 5 seconds?
(x/900)*5=10
To calculate the braking force required to stop the car, we need to use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration.
Here's how you can calculate the braking force:
1. First, we need to calculate the deceleration of the car, which is the negative acceleration because the car is slowing down. We can use the formula:
Acceleration (a) = (final velocity - initial velocity) / time
In this case, the final velocity is 0 m/s since the car comes to a stop, the initial velocity is 10 m/s, and the time is 5 seconds.
So, the acceleration is: (0 m/s - 10 m/s) / 5 s = -2 m/s^2
2. Since we now have the acceleration, we can calculate the braking force using Newton's second law:
Force (F) = mass (m) * acceleration (a)
The mass of the car is given as 900 kg, and the acceleration is -2 m/s^2.
So, the braking force is: F = 900 kg * (-2 m/s^2) = -1800 N
Note that the negative sign indicates that the force is acting in the opposite direction of motion, which, in this case, is towards stopping the car.
Therefore, the braking force required to stop the car in a time of 5 seconds is 1800 Newtons, acting in the opposite direction of its motion.