A chemist wants to be a supercook and wants to create 8%(m/v) acetic acud solution to be "extra strength" vinegar. if pure acetic acid Is a liquid density of 1.049 g/ml. how many ml of acetic acid should be dissolved to male 500 ml of 8% acetic acid?
Calculate grams of acetic acid needed by using %m/v formula then use density conversion factor given
8% m/v means 8 g acetic acid/100 mL soln. You want 500 mL soln so you want 5*8 = 40 g acetic acid.
volume = mass/density. You know mass and density, solve for volume needed for 40 grams
To calculate the grams of acetic acid needed to make 500 ml of 8% acetic acid solution, we need to follow a few steps.
Step 1: Calculate the grams of acetic acid needed using the %m/v formula:
The %m/v formula is:
%C = (grams of solute / ml of solution) * 100
Here we have:
%C = 8%
V = 500 ml
We need to find the grams of acetic acid.
So, rearranging the formula, we have:
Grams of solute = (%C * ml of solution) / 100
Substituting the values, we get:
Grams of acetic acid = (8% * 500 ml) / 100
Step 2: Convert grams to milliliters using the density conversion factor:
Since the density of pure acetic acid is given as 1.049 g/ml, we can use this information to convert the grams of acetic acid to milliliters.
Grams to milliliters conversion can be done by dividing the grams by the density:
Milliliters = Grams / Density
Substituting the values, we get:
Milliliters of acetic acid = (Grams of acetic acid) / (Density of acetic acid)
Calculating the final result:
First, let's calculate the grams of acetic acid using the %m/v formula:
Grams of acetic acid = (8% * 500 ml) / 100 = (0.08 * 500 ml) = 40 grams
Now, let's convert the grams to milliliters using the density conversion factor:
Milliliters of acetic acid = 40 grams / 1.049 g/ml ≈ 38.14 ml
Therefore, approximately 38.14 ml of acetic acid should be dissolved to make 500 ml of 8% acetic acid solution.