Algebra

-√3, 3√3 Write a quadratic equation in the variable X having the given numbers as solutions. Type in standard form ax^2 + bx +c =0

asked by Stella
  1. a x ^ 2 + b x + c = a ( x - x1 ) ( x - x2 )

    In this case :

    x 1 = sq

    posted by Bosnian
  2. a x ^ 2 + b x + c = a ( x - x1 ) ( x - x2 )


    a leading coefficient

    x1 and x2 roots


    In this case :

    x 1 = - sqrt ( 3)

    x 2 = 3 sqrt ( 3 )


    a x ^ 2 + b x + c = a [ ( x - ( - sqrt ( 3 ) ) ] * [ ( x - 3 sqrt ( 3 ) ) =

    a [ ( x + sqrt ( 3 ) ) ] * [ ( x - 3 sqrt ( 3 ) ) =

    a [ x * x + x * sqrt ( 3 ) - 3 sqrt ( 3 ) * x - 3 * sqrt ( 3 ) * sqrt ( 3 ) ] =

    a [ x ^ 2 - 2 sqrt ( 3 ) x - 3 * 3 ] =

    a [ x ^ 2 - 2 sqrt ( 3 ) x - 9 ]



    a [ x ^ 2 - 2 sqrt ( 3 ) x - 9 ] = 0 Divide both sides by a

    x ^ 2 - 2 sqrt ( 3 ) x - 9 = 0 / a

    x ^ 2 - 2 sqrt ( 3 ) x - 9 = 0

    posted by Bosnian

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