# Math

Find X

27^4x-2=243^3x+6

Please explain how to do it.

Thanks

27^(4x-2)=243^(3x+6)

Notice that 27 and 243 are both multiples of 3

Changing them..

(3^4)^(4x-2)=(3^6)^(3x+6)
3^4(4x-2)= 3^6(3x+6)

taking the log base 3 of each side.

(4x-2)= (3x+6)
and solve for x.

That doesn't work if you check it, did you do it wrong?

oops.

27^(4x-2)=243^(3x+6)

Notice that 27 and 243 are both multiples of 3

Changing them..

(3^4)^(4x-2)=(3^6)^(3x+6)
3^4(4x-2)= 3^6(3x+6)

taking the log base 3 of each side.

4(4x-2)= 6(3x+6)
and solve for x.

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1. 27^4x-2=243^3x+6 3^3(4x-2)=3^5(3x+6) 3(4x-2)=5(3x+6) 12x-6=15x+30 12x-15x=30+6 -3x=36 x=36/-3 x=-12

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