You are given a right triangle. The Opposit side length is 7 and the hypotenuse length is 9. What is the degree of the bigger angle? (The one closest to the 90* angle)
if x is the angle,
sin(x) = 7/9 = .77777
x = 51°
let the angle opposite the 7 unit side be Ø
sinØ = 7/9
Ø = 51.1°
( then the third angle would be 38.9° )
To find the degree of the bigger angle in a right triangle, we can use the inverse trigonometric function. In this case, we can use the sine function.
The sine of an angle is defined as the ratio of the length of the side opposite the angle (opposite side) to the length of the hypotenuse. In mathematical terms, sin(angle) = opposite/hypotenuse.
We are given that the opposite side length is 7 and the hypotenuse length is 9. So, sin(angle) = 7/9.
To find the angle, we can take the inverse sine (sin^(-1)) of 7/9 using a calculator or a trigonometric table.
Using a calculator, we find that the inverse sine of 7/9 is approximately 47.06 degrees (rounded to two decimal places).
Therefore, the degree of the bigger angle in the right triangle is approximately 47.06 degrees.