A droplet of ink in an industrial ink-jet printer carries a charge of 1.1×10−10 C and is deflected onto paper by a force of 3.7×10−4 N.Find the strength of the electric field to produce this force.
Hey there! Why did the droplet of ink get deflected onto the paper? Because it couldn't find a good charge to hang out with! Ah, ink humor!
Now, let's find the strength of the electric field required to produce this force. We can use the formula:
Force = Electric field strength x Charge
Given:
Force = 3.7×10^(-4) N
Charge = 1.1×10^(-10) C
We can rearrange the formula to solve for electric field strength:
Electric field strength = Force / Charge
Plugging in the values:
Electric field strength = (3.7×10^(-4) N) / (1.1×10^(-10) C)
Calculating that equation gives us a tremendous laughter! Just kidding, it gives us the electric field strength of:
Electric field strength ≈ 3.36 × 10^6 N/C
There you have it! The strength of the electric field required to produce this force is approximately 3.36 × 10^6 N/C. Keep those ink droplets charged up and happy!
To find the strength of the electric field, we can use the formula for the force experienced by a point charge in an electric field:
\[ F = q \cdot E \]
where F is the force, q is the charge, and E is the electric field strength. Rearranging the formula, we have:
\[ E = \frac{F}{q} \]
Given that the charge of the droplet of ink is q = 1.1×10^(-10) C and the force experienced by the droplet is F = 3.7×10^(-4) N, we can substitute these values into the formula to find the electric field strength:
\[ E = \frac{3.7×10^{-4} \, \text{N}}{1.1×10^{-10} \, \text{C}} \]
Calculating the equation gives us:
\[ E = 3.36×10^6 \, \text{N/C} \]
Therefore, the strength of the electric field to produce this force is 3.36×10^6 N/C.
To find the strength of the electric field that produces the force on the ink droplet, we can use the equation for the force experienced by a charged particle in an electric field:
F = q * E
Where:
F is the force experienced by the charged particle,
q is the charge of the particle, and
E is the electric field strength.
In this case, we are given:
q = 1.1×10^(-10) C (charge of the ink droplet)
F = 3.7×10^(-4) N (force experienced by the ink droplet)
We can rearrange the equation to solve for E:
E = F / q
Plugging in the given values:
E = (3.7×10^(-4) N) / (1.1×10^(-10) C)
To simplify this calculation, we can express the numbers in scientific notation:
E = (3.7 / 1.1) × (10^(-4) / 10^(-10)) N/C
Simplifying the exponents:
E = 3.36 × 10^6 N/C
Therefore, the strength of the electric field required to produce this force on the ink droplet is 3.36 × 10^6 N/C.
Force = q*E
Solve for the electric field
E = F/q
= 3.7*10^-4/1.1*10^-10
= 3.4*10^6 ,
in units of N/C. (Those units are the same as Volts/meter)