The solubility product expression for mercury(I) iodide, Hg2I2 is Ksp = ?
My answer is [Hg2^2+^][2I^-^]^2^
Would you agree?
See your post above.
Yes, I agree with your answer. The solubility product expression for mercury(I) iodide (Hg2I2) is indeed represented by the expression: [Hg2^2+^][2I^-^]^2^.
To understand how to derive this expression, you need to know that the solubility product constant (Ksp) is a measure of the extent to which a compound dissociates or dissolves in a solvent, in this case, water.
For the compound Hg2I2, it dissociates into two Hg2^2+ ions and two I^- ions when it dissolves in water:
Hg2I2(s) ⇌ 2Hg2^2+(aq) + 2I^-(aq)
The square brackets [ ] denote the concentration of each ion in the aqueous solution. In the case of Ksp expressions, as it represents the product of the ion concentrations raised to their stoichiometric coefficients, the Ksp expression for Hg2I2 becomes:
Ksp = [Hg2^2+][I^-]^2
Since there are two I^- ions in the dissociation equation, we square the concentration of I^- to account for the stoichiometry.
Therefore, your answer of Ksp = [Hg2^2+][2I^-]^2 is correct.