# physics

Two children on the beach are pulling on an inner tube. One exerts a force of 45 N[N]. The other exerts a force of 60N[SW]. What is the net force acting on the tube

1. Fn = 45N @ 90 Deg. + 60N @ 225 Deg.

X = 45*cos90 + 60*cos225 = -42.43 N.
Y = 45*sin90 + 60*sin225 = 2.57 N.

tanAr = Y/X = 2.57 / -42.43 = -0.06066.
Ar = -3.47 Deg.
A = -3.47 + 180 = 176.5 Deg.

Fn = X/cosA = -42.43 / cos176.5 = 42'51 N. @ 176.5 Deg.,CCW.

posted by Henry

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