I am having trouble answering this. please help!
Q: Cereol is a newly discovered compound in corn flakes. A biologist suspects that it increases mental ability. She is making a solution to test on rats.
First she makes a stock solution. She discovers that this is too concentrated, when the rats go on strike unless they are given french cheese. She takes 1 mL of the stock solution and dilutes it to 25 mL. She then dilutes this solution further, by taking 4 ml of the diluted solution and diluting it to a final volume of 250 mL.
How many times more concentrated is the original stock solution compared to the final dilutedsolution?
Let A = original concn.
New concn = A x (1/25) x (4/250) = ?
To find how many times more concentrated the original stock solution is compared to the final diluted solution, we need to calculate the dilution factor.
The dilution factor is the ratio of the final volume to the initial volume. In this case, the final volume is 250 mL, and the initial volume is 1 mL.
First, let's calculate the dilution factor for the first dilution:
Dilution factor = Final volume / Initial volume
Dilution factor = 25 mL / 1 mL
Dilution factor = 25
So, the first dilution factor is 25.
Next, let's calculate the dilution factor for the second dilution:
Dilution factor = Final volume / Initial volume
Dilution factor = 250 mL / 4 mL
Dilution factor = 62.5
So, the second dilution factor is 62.5.
To find the total dilution factor, we multiply the dilution factors of each dilution:
Total dilution factor = Dilution factor of first dilution × Dilution factor of second dilution
Total dilution factor = 25 × 62.5
Total dilution factor = 1562.5
Therefore, the original stock solution is 1562.5 times more concentrated than the final diluted solution.