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The problem to solve is: (x+20)(x12)(x+4)>0 but I can't figure out how to do this right so I left off the >0 and tried to solve the equation. x+20 evaluates to x+20 x12 evaluates to x12 Multiplying x+20 by x12 is a classic
asked by Sabrina on September 24, 2010 
Math
could you tell me three equivalent fractions for each: 2/3 8/16 4/10 3/4 Just multiply or divide by a common number. For example, 2/3 = 4/6 = 6/9 = 8/12 = 10/15 8/16 = 4/8 = 1/2 etc. Just multiply each fraction by 3 different
asked by Ann on November 28, 2006 
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my post is still on this page as algebra, could someone elaborate on what bobpursley tried to help me with. See your original post. I am guessing you are referring to your question 5)Simplify:(5x4)^2 and your answer= 25x^2  16
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Solve. x/91/7=26/63 STEP 1: The LCM is _________ To clear denominators, multiply each side of the equation by the LCM. _______/1 (x/91/7)=__________/1 multiply 26/63. STEP 2: Use the Distributive Property. _____/1 multiply x/9 
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.50  x / x = 3.20e1 I need to solve for x. I was going to do .50 X 3.20e1 and then take the square root but this is not correct. I am not sure what to do. Thank you for your help. Math(Please help)  Reiny, Tuesday, April 17,
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Ned divided a given number by 3 and then added 2. If he should have multiplied the number by 3 and then subtracted 2, which of the following two steps can he do next to get the correct answer? Subtract 4 and then multiply by 9.
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how do i do x2+12x+32 x2+12x = 14x+32 subtract 14x from each side 14x=32 divide by 2 7x=16 x=16/7, which is 2 and 2/7 ok maybe you typed that question wrong? is it x^2 + 12x + 32 ? if it is then the solution is: (x+8)(x+4) because
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20 x+3(y1)=11 2(xy)+8y = 28 multiply out 20 x+3y3=11  Is this correct? 2x+14y = 28 Using the addition method, would you multiply the first problem by 2 and the second by 20? No. In the second multiply out, you should have
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Which choice is the answer? Show me please. Tara spent 3 hours doing homework. She spent 1/3 of her time on math, and 1/5 on science. Which method would provide the most reasonable estimate of the totaltime Tara spent on her math
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